Stanislav Kalitskiy will fight against the Filipino Leon

Stanislav Kalitskiy (7-0) will fight with the Filipino boxer Landy Cris Leon (12-18-5). The eight-round fight will take place on May 18th as part of the RCC Boxing Promotions show in Ekaterinburg.

For Kalitskiy, the upcoming fight will be the eighth in his professional career, all of which were held at the RCC tournaments. All his previous fights were four- and six-round, and only three of them were over ahead of schedule. Kalitskiy is the third lightweight number in Kazakhstan.

Landy Cris Leon has more impressive experience - 35 fights behind his back, two of which were title fights. This will be the first fight of the Filipino in Russia, before that he performed only in his own country, China and Japan. He is 66th in the world lightweight ranking and eighth in the Philippines.

The tournament will take place at the RCC Academy of Martial Arts. The tournament starts at 17:00 Tickets ekb.kassir.ru ekb.kassy.ru

Broadcast 

 

Partners of RCC Boxing Promotions

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